Diameter = 6 in, Height = 8 in Radius = 3 in [ V = \pi (3)^2 (8) = \pi (9)(8) = 72\pi \ \textin^3 ] Using 3.14: ( 72 \times 3.14 = 226.08 \ \textin^3 ) Part 2: Practice Problems – Full Answers 1. Radius = 5 m, Height = 12 m ( V = \pi (25)(12) = 300\pi \ \textm^3 ) ≈ ( 942 \ \textm^3 )
( V = \pi (6.25)(6) = 37.5\pi \ \textft^3 ) ≈ ( 117.75 \ \textft^3 )
[ V = \pi r^2 h ]
Diameter = 6 in, Height = 8 in Radius = 3 in [ V = \pi (3)^2 (8) = \pi (9)(8) = 72\pi \ \textin^3 ] Using 3.14: ( 72 \times 3.14 = 226.08 \ \textin^3 ) Part 2: Practice Problems – Full Answers 1. Radius = 5 m, Height = 12 m ( V = \pi (25)(12) = 300\pi \ \textm^3 ) ≈ ( 942 \ \textm^3 )
( V = \pi (6.25)(6) = 37.5\pi \ \textft^3 ) ≈ ( 117.75 \ \textft^3 )
[ V = \pi r^2 h ]